Add:
$a - b + a b, b - c + b c, c - a + a c$ .

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Solution

If we add $a - b + a b, b - c + b c, c - a + a c$ then we get,
$(a - b + a b) + (b - c + b c) + (c - a + a c)$
$= a b + b c + c a$ .

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