Question

Add and express the sum as a mixed fraction:

$\left(i\right)$ $\frac{-12}{5}$ and $\frac{43}{10}$

Answer 1

Given: $\frac{-12}{5}$ and $\frac{43}{10}$

$\text{LCM}$ of denominators $5$ and $10=10$

$\therefore \frac{-12}{5}+\frac{43}{10}=\frac{-12\times 2}{5\times 2}+\frac{43}{10}$

$=\frac{-24}{10}+\frac{43}{10}$

$=\frac{-24+43}{10}$

$=\frac{19}{10}$

$=1\frac{9}{10}$

Hence, the required sum is $1\frac{9}{10}$