Let a=34a^2b+23a^2b #160; #160; #160; #160; #160; =(34+23)a^2b #160; #160; #160; #160; #160; #160; =(34×33+23×44)a ...

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Addition of Fractions

Add: 34a2b, ...

Question

Add: $\frac{3}{4} a^{2} b, \frac{2}{3} a^{2} b$

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Solution

Let $a = \frac{3}{4} a^{2} b + \frac{2}{3} a^{2} b$

$= (\frac{3}{4} + \frac{2}{3}) a^{2} b$

$= (\frac{3}{4} \times \frac{3}{3} + \frac{2}{3} \times \frac{4}{4}) a^{2} b$

$= (\frac{9}{12} + \frac{8}{12}) a^{2} b$

$= \frac{9 + 8}{12} a^{2} b$

$a = \frac{17}{12} a^{2} b$

$\frac{3}{4} a^{2} b + \frac{2}{3} a^{2} b = \frac{17}{12} a^{2} b$

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