Add $\frac{5}{8}$ and $\frac{- 11}{12}$

\frac{- 5}{24}

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\frac{- 3}{8}

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\frac{- 7}{12}

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\frac{- 7}{24}

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Solution

The correct option is D $\frac{- 7}{24}$
$\frac{5}{8} + \frac{- 11}{12}$
$= \frac{5}{8} + (\frac{- 11}{12})$
$= \frac{5 \times 3 - 11 \times 2}{24} = \frac{- 7}{24}$

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Similar questions

Add and express the sum as mixed fraction: (i) $\frac{- 12}{5} a n d \frac{43}{10}$ (ii) $\frac{24}{7} a n d \frac{- 11}{4}$ (iii) $\frac{- 31}{6} a n d \frac{- 27}{8}$ (iv) $\frac{101}{6} a n d \frac{7}{8}$

24 - [12 - {11 - (¯ ¯¯¯¯¯¯¯¯¯¯ ¯ 8 - 5 - 3)}]

Q. Evaluate the following :

8 \times \frac{\frac{5}{24}}{\frac{7}{12}}

source $(i) \frac{8}{9} + \frac{- 11}{6} (i i) 3 + \frac{5}{- 7} (i i i) \frac{1}{- 12} a n d \frac{2}{- 15} (i v) \frac{- 8}{19} + \frac{- 4}{57} (v) \frac{7}{9} + \frac{3}{- 4} (v i) \frac{5}{26} + \frac{11}{- 39} (v i i) \frac{- 16}{9} + \frac{- 5}{12} (v i i i) \frac{- 13}{8} + \frac{5}{36} (i x) 0 + \frac{- 3}{5} (x) 1 + \frac{- 4}{5} (x i) \frac{- 5}{16} + \frac{7}{24}$

Fill in the blanks.

(i) $(\frac{- 3}{17}) + (\frac{- 12}{5}) = (\frac{- 12}{5}) + (. . . . .)$

(ii) $- 9 + \frac{- 21}{8} = (. . . . . .) + (- 9)$

(iii) $(\frac{- 8}{13} + \frac{3}{7}) + (\frac{- 13}{4}) = (. . . . . .) + [\frac{3}{7} + (\frac{- 13}{4})]$

(iv) $- 12 + (\frac{7}{12} + \frac{- 9}{11}) = (- 12 + \frac{7}{12}) + (. . . . .)$

(v) $\frac{19}{- 5} + (\frac{- 3}{11} + \frac{- 7}{8}) = {\frac{19}{- 5} + (. . . . .)} + \frac{- 7}{8}$

(vi) $\frac{- 16}{7} + . . . . . = . . . . . . + \frac{- 16}{7} = \frac{- 16}{7}$

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Add 58 and −1112

The correct option is D −72458+−1112=58+(−1112)=5×3−11×224=−724

Add $\frac{5}{8}$ and $\frac{- 11}{12}$

The correct option is D $\frac{- 7}{24}$
$\frac{5}{8} + \frac{- 11}{12}$
$= \frac{5}{8} + (\frac{- 11}{12})$
$= \frac{5 \times 3 - 11 \times 2}{24} = \frac{- 7}{24}$