Question

Add he following fractions.
(vi) $3\frac{1}{8},5\frac{5}{12},\frac{5}{16}$

Answer 1

Step 1: Converting the mixed fractions into improper fractions.
Given fractions are $3\frac{1}{8},5\frac{5}{12},\frac{5}{16}$.
$\Rightarrow 3\frac{1}{8}=\frac{8\times 3+1}{8}=\frac{25}{8}$
$\Rightarrow 5\frac{5}{12}=\frac{12\times 5+5}{12}=\frac{65}{12}$

Step 2: Converting the fractions into like fractions.
$\Rightarrow 3\frac{1}{8}=\frac{25}{8}=\frac{25\times 6}{8\times 6}=\frac{150}{48}$
$\Rightarrow 5\frac{5}{12}=\frac{65}{12}=\frac{65\times 4}{12\times 4}=\frac{260}{48}$
$\Rightarrow \frac{5}{16}=\frac{5\times 3}{16\times 3}=\frac{15}{48}$

Step 3: Adding the fractions and converting into mixed fraction.
$\Rightarrow \frac{150}{48}+\frac{260}{48}+\frac{15}{48}$
$=\frac{150+260+15}{48}$
$=\frac{425}{48}$

Using, Quotient $\frac{\text{Remainder}}{\text{Divisor}}$ we have:
$\therefore \text{Required mixed fraction}=8\frac{41}{48}$.
Hence, $8\frac{41}{48}$ is the required answer.