Add the following:
6ab,-5ba,-3a2
Adding the algebraic expressions
Given terms are, 6ab,-5ba,-3a2
To add two or more terms, group the like terms and add each group of like terms separately.
So,
6ab+(-5ba)+(-3a2)=[6ab+(-5ba)]+(-3a2)=[6+(-5)]ab+(-3a2)=[6-5]ab-3a2=ab-3a2
Hence, the required answer is ab-3a2
Factorising the polynomial 3a2 + 6ab - 6a, we get
What must be subtracted from 3a2 − 6ab − 3b2 − 1 to get 4a2 − 7ab − 4b2 + 1?