MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Addition of Algebraic Expressions

Add the follo...

Question

Add the following:

$a (a + b), b (b + c), c (a + c)$ and $a^{2} + b^{2} + c^{2}$

Open in App

Solution

$\Rightarrow a (a + b) + b (b + c) + c (a + c) + a^{2} + b^{2} + c^{2}$

$\Rightarrow a^{2} + a b + b^{2} + b c + c^{2} + c a + a^{2} + b^{2} + c^{2}$

$\Rightarrow 2 a^{2} + 2 b^{2} + 2 c^{2} + a b + b c + c a$

Suggest Corrections

thumbs-up

3

Similar questions

Add the following:

$a (a + b), b (b + c), c (a + c) a n d a^{2} + b^{2} + c^{2}$ [2 MARKS]

Add the following:

$a (a + b), b (b + c), c (a + c) a n d a^{2} + b^{2} + c^{2}$ [2 MARKS]

Q. Prove the following identity:

\frac{a {(b - c)}^{2}}{(c - a) (a - b)} + \frac{b {(c - a)}^{2}}{(a - b) (b - c)} + \frac{c {(a - b)}^{2}}{(b - c) (c - a)} = a + b + c

Q. If a² + b² + c² + ab + bc + ca = 89 and (a + b) : (b + c) : (c + a) = 12 : 5 : 3, where a, b and c are real numbers, then (a² + b² + c² – ab – bc – ca) equals

यदि a² + b² + c² + ab + bc + ca = 89 तथा (a + b) : (b + c) : (c + a) = 12 : 5 : 3, जहाँ a, b व c वास्तविक संख्याएँ हैं, तब (a² + b² + c² – ab – bc – ca) बराबर है

a^{2} + b^{2} + c^{2} - a b - b c - c a = \frac{1}{2} [{(b - c)}^{2} + {(c - a)}^{2} + {(a - b)}^{2}]

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Addition of Algebraic Expressions

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Addition of Algebraic Expressions

Standard VII Mathematics

Join BYJU'S Learning Program

CrossIcon