Add the following :-
$a b - b a, b c - c a, c a - a b$

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Solution

$a b - b a + b c - c a + c a - a b = - b a + b c$
$=$ $b (c - a)$

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Similar questions

a b - b c, b c - c a, c a - a b

a b - b c, b c - c a, c a - a b

Question 57 (c)

Add the following expression:

ab + bc + ca and - bc - ca - ab

(a b + b c) (a b - b c) + (b c + c a) (b c - a c) + (c a + a b) (a c - a b)

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