Add the following expressions: $3 x + y - 8$ and $y + 4 - 7 x$

4 x + 2 y - 4

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- 4 x + 2 y - 4

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- 4 x + 3 y - 4

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4 x + 3 y + 4

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Solution

The correct option is B $- 4 x + 2 y - 4$
Adding $(3 x + y - 8)$ and $(y + 4 - 7 x)$ ,
$3 x + y - 8$
$- 7 x + y + 4$
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$- 4 x + 2 y - 4$

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Similar questions

(x + y)^{4} = x^{4} + 4 x^{3} y + 6 x^{2} y^{2} + 4 x y^{3} + y^{4}

3 x - 2 y + 3 z = 8

2 x + y - z = 1

4 x - 3 y + 2 z = 4

(x - y)^{4} = x^{4} - 4 x^{3} y + 6 x^{2} y^{2} - 4 x y^{3} + y^{4}

Question 83 (xviii)

Multiply the following :

$(\frac{3}{4} x - \frac{4}{3} y), (\frac{2}{3} x + \frac{3}{2} y)$

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