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Question

Add the following expressions using both the horizontal method and column method:

2ab-3a2b+7ab2,4ab2+5a2b-3ab and 7a2b-10ab2+3ab


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Solution

Step 1: Adding the algebraic expressions by the horizontal method

Horizontal method: Taking care of signs, write all expressions in a horizontal line and group like terms together. Now, add these like terms and get the required sum.

We have 2ab-3a2b+7ab2,4ab2+5a2b-3ab and 7a2b-10ab2+3ab

Now,

(2ab-3a2b+7ab2)+(4ab2+5a2b-3ab)+(7a2b-10ab2+3ab)=2ab-3a2b+7ab2+4ab2+5a2b-3ab+7a2b-10ab2+3ab=2ab-3ab+3ab-3a2b+5a2b+7a2b+7ab2+4ab2-10ab2=(2-3+3)ab+(-3+5+7)a2b+(7+4-10)ab2=(2)ab+(9)a2b+(1)ab2=2ab+9a2b+ab2

Step 2: Adding the algebraic expressions by the column method

Column method: Write each expression in separate lines such that their like terms lie in the same vertical column. Taking care of signs, add each column.

2ab-3a2b+7ab2-3ab+5a2b+4ab2+3ab+7a2b-10ab2__________________2ab+9a2b+ab2___________________

Hence, the required sum is 2ab+9a2b+ab2


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