Question

Add the following fractions.​

$1\frac{7}{8},1\frac{1}{2},1\frac{3}{4}$

Answer 1

Step 1: Converting the mixed fraction into improper fraction

$1\frac{7}{8}=\frac{1\times 8+7}{8}=\frac{15}{8}$

$1\frac{1}{2}=\frac{1\times 2+1}{2}=\frac{3}{2}$

$1\frac{3}{4}=\frac{1\times 4+3}{4}=\frac{7}{4}$

Step 2: Converting the fractions into like fractions

$\frac{15}{8}=\frac{15\times 1}{8\times 1}=\frac{15}{8}$

$\frac{3}{2}=\frac{3\times 4}{2\times 4}=\frac{12}{8}$

$\frac{7}{4}=\frac{7\times 2}{4\times 2}=\frac{14}{8}$

Step 3: Adding the ftactions and converting into mixed fraction

$\frac{15}{8}+\frac{12}{8}+\frac{14}{8}$

$=\frac{15+12+14}{8}$
$=\frac{41}{8}$

Using, $\text{quotient}\frac{\text{remainder}}{\text{divisor}}$ we have,
required mixed fraction is $5\frac{1}{8}$