Question

Add the following fractions.​ ​
$3\frac{3}{4},2\frac{1}{6}\text{and}1\frac{5}{8}$

Answer 1

Step 1: Converting all mixed fractions into improper fractions

$3\frac{3}{4}=\frac{3\times 4+3}{4}=\frac{15}{4}$

$2\frac{1}{6}=\frac{2\times 6+1}{6}=\frac{13}{6}$

$1\frac{5}{8}=\frac{1\times 8+5}{8}=\frac{13}{8}$

Step 2: Converting all the fractions into like fractions

$\frac{15}{4}=\frac{15\times 6}{4\times 6}=\frac{90}{24}$

$\frac{13}{6}=\frac{13\times 4}{6\times 4}=\frac{52}{24}$

$\frac{13}{8}=\frac{13\times 3}{8\times 3}=\frac{39}{24}$

Step 3: Adding all the fractions and converting into mixed fraction

$\frac{90}{24}+\frac{52}{24}+\frac{39}{24}$

$=\frac{90+52+39}{24}$

$=\frac{181}{24}$


Using, $\text{quotient}\frac{\text{remainder}}{\text{divisor}}$ we have, required answer is $7\frac{13}{24}$