Question

Add the following lengths:

$kmmcm$

$16$ $800$ $25$

+$25$ $200$ $80$

$$\begin{gathered} \_\_\_\_\_\_\_\_\_\_\_\_\_\_ \\ \_\_\_\_\_\_\_\_\_\_\_\_\_\_ \end{gathered}$$

Answer 1

Find the sum

We know, when we add quantities like these, we add the similar quantities and get the final answer be converting the smaller unit to the larger unit if required.

Here, the given quantities :$16\mathrm{km}800\mathrm{m}25\mathrm{cm}$, $25\mathrm{km}200\mathrm{m}80\mathrm{cm}$ can be added as shown below:

When we add the length we get

$kmmcm$

$16$ $800$ $25$

+ $25$ $200$ $80$

$$\begin{gathered} \_\_\_\_\_\_\_\_\_\_\_\_\_ \\ 411000105 \\ \_\_\_\_\_\_\_\_\_\_\_\_\_ \end{gathered}$$

We know that

$100\mathrm{cm}$ $=1\mathrm{m}$

$105\mathrm{cm}=\left(100+5\right)\mathrm{cm}=1\mathrm{m}5\mathrm{cm}$

Thus, $41\mathrm{km}1000\mathrm{m}105\mathrm{cm}=41\mathrm{km}1000\mathrm{m}+1\mathrm{m}5\mathrm{cm}=41\mathrm{km}1001\mathrm{m}5\mathrm{cm}$

Also, We know that :

$1000\mathrm{m}=1\mathrm{km}$

$1001\mathrm{m}=\left(1000+1\right)\mathrm{m}=1\mathrm{km}1\mathrm{m}$

Thus, $41\mathrm{km}1001\mathrm{m}5\mathrm{cm}=41\mathrm{km}+1\mathrm{km}+1\mathrm{m}+5\mathrm{cm}$

$=42\mathrm{km}1\mathrm{m}5\mathrm{cm}$

Hence, the final answer is $42\mathrm{km}1\mathrm{m}5\mathrm{cm}$.