Question

Add the following rational numbers:
(i) $\frac{-2}{5}\mathrm{and}\frac{4}{5}$
(ii) $\frac{-6}{11}\mathrm{and}\frac{-4}{11}$
(iii) $\frac{-11}{8}\mathrm{and}\frac{5}{8}$
(iv) $\frac{-7}{3}\mathrm{and}\frac{1}{3}$
(v) $\frac{5}{6}\mathrm{and}\frac{-1}{6}$
(vi) $\frac{-17}{15}\mathrm{and}\frac{-1}{15}$

Answer 1

1. $\frac{-2}{5}+\frac{4}{5}=\frac{-2+4}{5}=\frac{2}{5}$


2. $\frac{-6}{11}+\frac{-4}{11}=\frac{-6+(-4)}{11}=\frac{-6-4}{11}=\frac{-10}{11}$


3. $\frac{-11}{8}+\frac{5}{8}=\frac{-11+5}{8}=\frac{-6}{8}=\frac{-3\times 2}{4\times 2}=\frac{-3}{4}$


4. $\frac{-7}{3}+\frac{1}{3}=\frac{-7+1}{3}=\frac{-6}{3}=\frac{-3\times 2}{3}=-2$


5. $\frac{5}{6}+\frac{-1}{6}=\frac{5+(-1)}{6}=\frac{4}{6}=\frac{2\times 2}{3\times 2}=\frac{2}{3}$


6. $\frac{-17}{15}+\frac{-1}{15}=\frac{-17+(-1)}{15}=\frac{-17-1}{15}=\frac{-18}{15}=\frac{-6\times 3}{5\times 3}=\frac{-6}{5}$