Question

Add. Write each sum in the lowest terms.

$$\begin{gathered} \frac{1}{3} \\ +\frac{1}{4} \end{gathered}$$

Answer 1

While adding fraction having, unlike denominators. The least common multiple of the denominators is always the least common denominator.

Also, we can use the product of the denominators to get a common denominator keeping in mind that the denominators are prime.

We have $\frac{1}{3}+\frac{1}{4}$

The least common multiple of the denominators $(3,4)=12$

$$\begin{gathered} =\frac{1}{3}+\frac{1}{4} \\ =\frac{4}{12}+\frac{3}{12}(changing\frac{1}{3}\&\frac{1}{4}inequivalentfractionhavingdenominatoras12) \\ =\frac{7}{12} \end{gathered}$$

Therefore the required sum in the lowest term is $\frac{7}{12}$