Question

Add. Write each sum in the lowest terms.

$$\begin{gathered} \frac{1}{4} \\ +\frac{1}{6} \end{gathered}$$

Answer 1

While adding fraction having, unlike denominators. The least common multiple of the denominators is always the least common denominator.

Also, we can use the product of the denominators to get a common denominator keeping in mind that the denominators are prime.

We have $\frac{1}{4}+\frac{1}{6}$

The least common multiple of the denominators $(4,6)=12$

$$\begin{gathered} =\frac{1}{4}+\frac{1}{6} \\ =\frac{3}{12}+\frac{2}{12}(changing\frac{1}{4}\&\frac{1}{6}inequivalentfractionhavingdenominatoras12) \\ =\frac{5}{12} \end{gathered}$$

Therefore the required sum in the lowest term is $\frac{5}{12}$