Question

Add. Write each sum in the lowest terms.

$$\begin{gathered} \frac{1}{4} \\ +\frac{3}{10} \end{gathered}$$

Answer 1

While adding fraction having, unlike denominators. The least common multiple of the denominators is always the least common denominator.

Also, we can use the product of the denominators to get a common denominator keeping in mind that the denominators are prime.

We have $\frac{1}{4}+\frac{3}{10}$

The least common multiple of the denominators $(4,10)=20$

$$\begin{gathered} =\frac{1}{4}+\frac{3}{10} \\ =\frac{5}{20}+\frac{6}{20}(changing\frac{1}{4}\&\frac{3}{10}inequivalentfractionhavingdenominatoras20) \\ =\frac{11}{20} \end{gathered}$$

Therefore the required sum in the lowest term is $\frac{11}{20}$