Addiction of HCl to 3, 3-dimethyl - 1 - butene yields two products, one of which has a rearranged carbon skeleton. Among the following carbocations, select the possible intermediates in that reaction.
$(C H_{3})_{3} C C^{+} H C H_{2} C l$ $(C H_{3})_{3} C C^{+} H C H_{3}$ (CH_3)_2 $(C H_{3})_{2} C | C l + C (C H_{3})_{2}$ $(C H_{3})_{2} + C C H (C H_{3})_{2}$

1,2

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1,3

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1,4

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2,3

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2,4

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Solution

The correct option is D 2,4
As refer to the IMAGE $01$ that is $3 - 3 - d i m e t h y l - b u t - 1 - e n e$ .
The intermediates on reaction with $H C l$ are as shown in the IMAGE $02$

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Similar questions

Which of the following carbocation is most stable?
(a) $(C H_{3})_{3} C . + C H_{2}$ (b) $(C H_{3})_{3} + C$
(c) $C H_{3} C H_{2} + C H_{2}$ (d) $C H_{3} + C H C H_{2} C H_{3}$

Q. The addition of HBr to

3

- m e t h y l -

- b u t e n e

leads to several products.One of these products, the major product, in fact, is formed via a rearranged carbocation. Identify that product?

Q. The intermediate stages in the conversion:

\begin{matrix} {(C H_{3})}_{2} - C & - C - & {(C H_{3})}_{2} | & | O H & O H \end{matrix} d i l . H_{2} S O_{4} ⟶ Δ C H_{3} C O C {(C H_{3})}_{3}

Q. Assertion :Addition of

H C l

3

-methyl-

1

-butene gives

2

-chloro-

2

-methyl butane as the major product. Reason: Rearrangement of carbocation to more stable carbocation leads to formation of major product.

Q. Give the major product of the following reaction:

3, 3

-dimethyl-

1

-butene

+ H C l \to M a j o r

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Addiction of HCl to 3, 3-dimethyl - 1 - butene yields two products, one of which has a rearranged carbon skeleton. Among the following carbocations, select the possible intermediates in that reaction. (CH3)3CC+HCH2Cl (CH3)3CC+HCH3 (CH_3)_2 (CH3)2C|Cl+C(CH3)2 (CH3)2+CCH(CH3)2

The correct option is D 2,4As refer to the IMAGE 01 that is 3−3−dimethyl−but−1−ene.The intermediates on reaction with HCl are as shown in the IMAGE 02

The correct option is D 2,4
As refer to the IMAGE $01$ that is $3 - 3 - d i m e t h y l - b u t - 1 - e n e$ .
The intermediates on reaction with $H C l$ are as shown in the IMAGE $02$