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Question

Adding powdered Pb and Fe to a solution containing 1.0 M each of Pb2+ and Fe2+ ions would result in the formation of:
(Given : EoPb2+/Pb= - 0.13 V and EoFe2+/Fe = -0.44 V at 298 K)

A
More of Pb and Fe2+ ions
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B
More of Fe and Pb2+ ions
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C
More of Pb and Fe
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D
More of Pb2+ and Fe2+ ions
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Solution

The correct option is A More of Pb and Fe2+ ions
As the value of standard electrode potential for Pb2+ is more than that of Fe2+ i.e.
EPb2+/Pb>EFe2+/Fe
So, Fe will get oxidised and Pb2+ will get reduced. Hence, we will have more of Pb and Fe2+ ions.

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