The correct option is A more of Pb and Fe2+ ions
The standard reduction potential of Pb+2|Pb electrode is −0.126 V which less negative than the standard reduction potential of Fe2+|Fe electrode which is −0.44 V
Hence, Pb2+ ions are reduced to Pb and Fe is oxidized to Fe2+.
Adding powdered Pb and Fe to a solution containing 1 M each of Pb2+ and Fe2+ ions would result in the formation of more of Pb and Fe2+ ions.