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Question


Adding powdered Pb and Fe to a solution containing 1 M each of Pb2+ and Fe2+ ions would result in the formation of: (E0Pb2+/Pb=−0.126V,E0Fe2+/Fe=−0.44V)

A
more of Pb and Fe2+ ions
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B
more of Fe and Pb2+ ions
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C
more of Pb and Fe
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D
more of Pb2+ and Fe2+ ions
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Solution

The correct option is A more of Pb and Fe2+ ions
The standard reduction potential of Pb+2|Pb electrode is 0.126 V which less negative than the standard reduction potential of Fe2+|Fe electrode which is 0.44 V
Hence, Pb2+ ions are reduced to Pb and Fe is oxidized to Fe2+.
Adding powdered Pb and Fe to a solution containing 1 M each of Pb2+ and Fe2+ ions would result in the formation of more of Pb and Fe2+ ions.

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