CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Addition of a non-volatile solute to a solvent always increases the colligative property such as π,ΔPP,ΔTb and ΔTf. All these colligative properties are directly proportional to the molality. The increase in colligative properties is due to increase in number of solute particles.
If relative decrease in vapour pressure is 0.4 for a solution containing 1 mole NaCl in 3 moles of H2O, then what is the percentage ionization of NaCl?

 
  1. 100%
  2. 60%
  3. 80%
  4. 40%


Solution

The correct option is A 100%
Let the degree of dissociation be α.
then i = 1 + α (for NaCl)
ΔPP=inNaClinNaCl+nH2O
0.4=(1+α)×1(1+α)×1+3
25(1+α)(4+α)
8+2α=5+5α
3α=3
α=1
100%

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


People also searched for
View More



footer-image