Addition of excess aqueous ammonia to a pink coloured aqueous solution of $M C l_{2} .6 H_{2} O (X)$ and $N H_{4} C l$ gives an octahedral complex Y in the presence of air. In aqueous solution, complex Y behaves as 1 :3 electrolyte. The reaction of X with excess $H C l$ at room temperature results in the formation of a blue coloured complex Z. The calculated spin only magnetic moment of X and Z is 3.87 B.M., whereas it is zero for the complex Y. Among the following options, which statement(s) is/are correct?

The hybridization of the central metal ion in Y is

d^{2} s p^{3}

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Z is a tetrahedral complex

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Addition of silver nitrate to Y gives only two equivalents of silver chloride

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When X and Z are in equilibrium at

0^{\circ} C

, the colour of the solution is pink

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Solution

The correct option is D When X and Z are in equilibrium at $0^{\circ} C$ , the colour of the solution is pink
$[C o (H_{2} O)_{6} (X)] O c t a h e d r a l (p i n k) (μ = 3.87 B . M .) C l_{2} A q . N H_{3} + N H_{4} C l - --------- \to a i r [C o (N H_{3})_{6}] C l_{3} (Y) (μ = 0)$

1:3 elctrolyte means $3 C l^{-} a n d o n e [C o (N H_{3})_{6}]^{3 +}$

Y is inner-orbital complex having $d^{2} s p^{3}$ hybridization and thus, all the electrons are paired in the complex.

$[C o (H_{2} O)_{6} (X)]^{2 +} + H C l (e x c e s s) 0^{\circ} C ⇌ [C o C l_{4}]^{2 -} t e t r a h e d r a l (b l u e) (μ = 3.87 B . M .), Δ H = + v e$

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Similar questions

Q. Addition of excess aqueous ammonia to a pink coloured aqueous solution of

M C l_{2} .6 H_{2} O (X)

and

N H_{4} C l

gives an octahedral complex Y in the presence of air. In aqueous solution, complex Y behaves as 1 :3 electrolyte. The reaction of X with excess

H C l

at room temperature results in the formation of a blue coloured complex Z. The calculated spin only magnetic moment of X and Z is 3.87 B.M., whereas it is zero for the complex Y. Among the following options, which statement(s) is/are correct?

Q. Addition of excess aqueous ammonia to a pink coloured aqueous solution of

M C l_{2} .6 H_{2} O (X)

and

N H_{4} C l

gives an octahedral complex Y in the presence of air. In aqueous solution, complex `I behaves as I :3 electrolyte. The reaction of X with excess HCI at room temperature results in the formation of a blue coloured complex Z. The calculated spin only magnetic moment of X and Z is 3.87 B.M.. whereas it is zero for complex Y.
Among the following options, which statements is(are) CORRECT ?

Q. Addition of excess aqueous ammonia to a pink coloured aqueous solutions of

M C l_{2} .6 H_{2} O (X) and N H_{4} C l

gives an octahedral complex Y in the presence of air. In aqueous solution, complex Y behaves as 1 : 3 electrolyte. The reaction of X with excess HCl at room temperature results in the formation of a blue coloured complex Z. The calculated spin only magnetic moment of X and Z is 3.87 B.M., whereas it is zero for complex Y. Among the following options, which statement(s) is/are correct?

Addition of excess aqueous ammonia to a pink coloured aqueous solution of $M C l_{2} . H_{2} O (x) a n d N H_{4} C l$ gives an octahedral complex Y in the presence of air. In aqueous solution, complex Y behaves as 1:3 electrolyte. The reaction of X with excess HCl at room temperature results in the formation of a blue coloured complex Z. The calculated spin only magnetic moment of X and Z is 3.87 B.M., whereas it is zero for complex Y.
Among the following options, which statemet(s) is (are) correct?