Question

Addition of small amount of ($C_2{H}_5{)}_4$Pb to a mixture of methane and chlorine, starts the reaction at ${140}^{\circ }$instead of the usual minimum ${250}^{\circ }$C.
If true enter 1,if false enter 0.

Answer 1

Answer 1

Cholrination of methyl takes place at ${250}^o$C. The reaction mechanism opted by free radicals. Tetraethyllead $(C_2{H}_5{)}_{4}Pb$ dissociates and form free radical at lower temperature. That in turn induce the formation of Chlorine free radical. The reaction do not require to achieve bond dissociation energy for the formation of $C{l}^{\ast }$ free radical and the halogenation reaction takes place at ${140}^{o}C$ instead of ${250}^{o}C$