Question

Additive inverse of $\frac{7}{5}$ is:

Answer 1

An additive inverse of a number is defined as the value, which on adding with the original number results in zero value. It is the value we add to a number to yield zero. Suppose, $a$is the original number, then its additive inverse will be minus of $a$ i.e., $-a$, such that;

$a+(-a)=a–a=0$

The additive inverse of $\frac{7}{5}$ is $-\frac{7}{5}$

When we add $-\frac{7}{5}$ in$\frac{7}{5}$the result is zero.

$$\begin{gathered} \Rightarrow \frac{7}{5}+\left(\frac{-7}{5}\right)=\left(\frac{-7}{5}\right)–\frac{7}{5} \\ =0 \end{gathered}$$

Hence, The additive inverse of $\frac{7}{5}$ is $-\frac{7}{5}$.