Question

# Additive inverse of $\frac{7}{5}$ is:

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Solution

## An additive inverse of a number is defined as the value, which on adding with the original number results in zero value. It is the value we add to a number to yield zero. Suppose, $a$is the original number, then its additive inverse will be minus of $a$ i.e., $-a$, such that;$a+\left(-a\right)=a–a=0$The additive inverse of $\frac{7}{5}$ is $-\frac{7}{5}$When we add $-\frac{7}{5}$ in$\frac{7}{5}$the result is zero.$⇒\frac{7}{5}+\left(\frac{-7}{5}\right)=\left(\frac{-7}{5}\right)–\frac{7}{5}\phantom{\rule{0ex}{0ex}}=0$Hence, The additive inverse of $\frac{7}{5}$ is $-\frac{7}{5}$.

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