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Hyperconjugation

Adenosine tri...

Question

Adenosine triphoshate (ATP) molecule is given above. Calculate value of $n_{1} + n_{2}$ , where $n_{1}$ is the net negative charge in neutral medium and $n_{2}$ is number of chiral carbon atoms.

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Solution

The correct option is A 8
In neutral medium, each OH group is acidic and deprotonates, leaving a negative charge on oxygen. There are four such OH groups. The OH groups on the furan ring are not acidic as two negative charges are not stable on adjacent atoms, in space. Hence, $n_{1} = 4$ . ATP contains 4 chiral carbon atoms which are marked with asterisk. Hence, $n_{2} = 4$ . Thus, $n_{1} + n_{2} = 4 + 4 = 8$ .

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Adenosine triphoshate (ATP) molecule is given above. Calculate value of n1+n2, where n1 is the net negative charge in neutral medium and n2 is number of chiral carbon atoms.

Adenosine triphoshate (ATP) molecule is given above. Calculate value of $n_{1} + n_{2}$ , where $n_{1}$ is the net negative charge in neutral medium and $n_{2}$ is number of chiral carbon atoms.