Adsorption of gas on a surface follows Freundlich adsorption isotherm. Plot of logx/m versus logP gives a straight line with slope equal to 0.5, then:
(x/m is the mass of the gas adsorbed per gram of adsorbent)
A
Adsorption is proportional to the square of pressure
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Adsorption is independent to pressure
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Adsorption is proportional to the pressure
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Adsorption is proportional to the square root of pressure
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D Adsorption is proportional to the square root of pressure According to Freundlich isotherm, xm=kP1/n
Taking log on both side logxm=logk+1nlogP y=c+mx
Here, 1/n represents slope =0.5
So xm=kP1/n ⇒xm∝√P
Hence, the correct option is d.