AF : CH : : KT : ?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D MV
As,
$A + 2 - \to C$
$F + 2 - \to H$
Similarly,
$K + 2 - \to M$
$T + 2 - \to V$

Suggest Corrections

Similar questions

Q. If

(f^{2} - b c) x + (c h - f g) y + (b g + h f) z = 0

(c h - f g) x + (g^{2} - c a) y + (a f - g h) z = 0

(b g - h f) x + (a f - g h) y + (h^{2} - a b) z = 0

,
show that

a b c + 2 f g h - a f^{2} - b g^{2} - c h^{2} = 0

Q. The striaght lines whose direction cosines satisfies

a l + b m + c n = 0, f m n + g n l + h l m = 0

are perpendicular or parallel if

Q. Prove

∣ ∣ ∣ ∣ \begin{matrix} a h + b g & g & a b + c h b f + b a & f & h b + b c a f + b c & d & b g + f c \end{matrix} ∣ ∣ ∣ ∣ = ∣ ∣ ∣ ∣ \begin{matrix} a h + b g & a & h b f + b a & h & b a f + b c & g & f \end{matrix} ∣ ∣ ∣ ∣

If the equation
$a x^{2} + 2 h x y + b y^{2} + 2 g x + 2 f y + c = 0$
represents a pair of straight lines, then
$a b c + 2 f g h - a f^{2} - b g^{2} + c h^{2} = 0$

Q. Polygon

A B C D E

is divided into parts as shown in adjoining figure. Find its area if

A D = 8 c m, A H = 6 c m, A G = 4 c m, A F = 3 c m

and perpendiculars

B F = 2 c m, C H = 3 c m, E G = 2.5 c m .

Join BYJU'S Learning Program

AF : CH : : KT : ?

The correct option is D MVAs,A+2−→CF+2−→HSimilarly,K+2−→MT+2−→V

The correct option is D MV
As,
$A + 2 - \to C$
$F + 2 - \to H$
Similarly,
$K + 2 - \to M$
$T + 2 - \to V$