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Law of Radioactivity

After 2hours,...

Question

After 2hours, one-sixteenth of the starting amount of a certain radioactive isotope remained undecayed.The half-life of the isotope is

A

15min

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B

30min

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C

45min

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D

1hour

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Solution

The correct option is B
30min

$\frac{N_{0}}{16} = \frac{N_{0}}{2^{n}} n = 4 t_{1 / 2} = \frac{1}{4} = \frac{1}{2} h r$

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