After 7 years Sarosh's father age will be 3 times that of Sarosh's age which will be simultaneously equal to 6 times of Sarosh's present age. Sum of their present ages is equal to: [4 MARKS]

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Solution

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Let Sarosh's present age be $x$

After 7 years, Sarosh's age will be $x + 7$

Father's age after 7 years is $3 (x + 7)$

This is equal to 6 times Sarosh's present age $= 6 x$

So, $6 x = 3 (x + 7) = 3 x + 21$

$\Rightarrow 6 x = 3 x + 21$

$\Rightarrow 6 x - 3 x = 21$

$\Rightarrow 3 x = 21$

$\Rightarrow x = \frac{21}{3} = 7$

Sarosh's present age is 7 years.

Father's age after 7 years is $6 \times 7 = 42 y e a r s$

His present age is $42 - 7 = 35 y e a r s$

Sum of their present ages $= 35 + 7 = 42$

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