After balancing the following reaction, what will be the sum of the all coefficients?
$C_{6} H_{12} O_{6} + O_{2} \to C O_{2} + H_{2} O$

20

No worries! We‘ve got your back. Try BYJU‘S free classes today!

38

No worries! We‘ve got your back. Try BYJU‘S free classes today!

21

No worries! We‘ve got your back. Try BYJU‘S free classes today!

19

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

18

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $19$
Full balanced chemical equation is as follows :
$C_{6} H_{12} O_{6} + 6 O_{2} \to 6 C O_{2} + 6 H_{2} O$

Sum of coefficients $= 1 + 6 + 6 + 6 = 19$ .

Suggest Corrections

Similar questions

___C_{6} H_{6} +___O_{2} \to___{C O}_{2} +___H_{2} O

C_{6} H_{12} O_{6} ⟶ C_{2} H_{5} O H + C O_{2}

F e + O_{2} ⟶ {F e}_{2} O_{3}

N H_{3} + {C l}_{2} ⟶ N_{2} H_{4} + N H_{4} C l

N a + H_{2} O ⟶ N a O H + H_{2}

. . . C_{4} H_{10} + . . . . O_{2} \to . . . . C O_{2} + . . . . H_{2} O

C_{6} H_{12} O_{6}

H_{2} O

C_{12} H_{22} O_{11} + H_{2} O \to C_{6} H_{12} O_{6} + C_{6} H_{12} O_{6}

2.12 \times 10^{- 4} L {m o l}^{- 1} {s e c}^{- 1}

27^{o} C

1.07 \times 10^{5} J {m o l}^{- 1}

37^{o} C

Join BYJU'S Learning Program