Question

After completion of the reactions (I and II), the organic compound(s) in the reaction mixtures is/are

• A. Reaction I : P and reaction II: P
• B. Reaction I: U, acetone and reaction II: Q, acetone
• C. Reaction I: T, U acetone and reaction II: P
• D. Reaction I: R, acetone and reaction II : S, acetone

Answer 1

The correct option is C Reaction I: T, U acetone and reaction II: P

When acetone reacts with Br₂ in basic medium, bromoform is formed.

When $C{H}_{3}COC{H}_3$ and $B{r}_2$ are in equimolar quantity, all the $B{r}_2$ (limiting reactant) is converted into desired products and 2/3 mole of $C{H}_{3}COC{H}_3$ remains unreacted, being in excess.
When acetone reacts with $B{r}_2$ in acidic medium, there is monobromination of acetone.
$\underset{1mol}{C{H}_{3}COC{H}_3}+\underset{1mol}{B{r}_2}\stackrel{C{H}_{3}COOH}{\to }\underset{\left(P\right)}{C{H}_{3}COC{H}_{2}Br}+HBr$
$C{H}_{3}COC{H}_3$ and $B{r}_2$ react in 1:1 mole ratio and (P) is formed.
In reaction I, (U) and (T) are formed and acetone (reactant) remains unreacted. In reaction II, (P) is formed.