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Question

# After covering a distance of 30km. With a uniform speed there is some defect in a train enzine and therefore its speed is reduce to 4/5 of its original speed consiquetely the train reaches its destination late by 45 minutes had it happened after covering 18km. More the train would have reached 9 minutes earlier find the speed of the train and distance of journey.

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Solution

## Let, the speed of the train=xkm/hr the total distance covered by the train =ykm Original time taken to reach the destination =yx hrs. Reduced speed of train =4x5 km/hr According to the first condition, we getTime taken at original speed + time taken at reduced speed = original time taken +45 minutes 30x+y−304x5=yx+4560 After solving .we get Y−3x = 30 ……..(1) According to the second condition, we get 48x+y−484x5=yx+36 After solving 5y−12=240 ………(2) Solve equation (1) and (2) ,we get x=30 ,y = 120 Therefore original speed of train = 30 km/hr and distance of journey = 120 km

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