Question

After $\gamma$ decay what would be the daughter element produced by technetium-99m (an isomer of ${}^{99}Tc$ with atomic number 43 and mass number 99) ?

• A. ${}_{43}^{98}Tc$
• B. ${}_{42}^{99}Mo$
• C. ${}_{44}^{99}Ru$
• D. ${}_{41}^{95}Nb$
• E. ${}_{43}^{99}Tc$

Answer 1

The correct option is E ${}_{43}^{99}Tc$

After γ decay ${}_{43}^{99}Tc$ would be the daughter element produced by technetium-99m (an isomer of 99Tc with atomic number 43 and mass number 99).
${}_{43}^{99}Tc{\to }_{43}^{99}Tc{+}_0^0\gamma$
Gamma particles have mass number 0 and atomic number 0.