After doing experiment- it is found that a saturated solution of BaSO4 at 25oC contains 3-9- 10-5 mole -liter of Ba2- ion- What is the value of Ksp of the BaSO4-

The correct option is D 1.5× 10^ 9 Ksp( Ba SO _ 4 ) = S ^ 2 BaSO _ 4 ⇌ Ba ^ 2+ + So _ 4 ^ 2 #160; #160; #160; #160; #160 ...

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Byju's Answer

Standard XII

Chemistry

Solubility Product

After doing e...

Question

After doing experiment, it is found that a saturated solution of $B a S O_{4}$ at $25^{o}$ C contains $3.9 \times 10^{- 5}$ mole $/$ liter of $B a^{2 +}$ ion. What is the value of $K_{s p}$ of the $B a S O_{4}$ ?

1.5 \times 10^{- 4}

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1.5 \times 10^{- 9}

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1.5 \times 10^{- 10}

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3.9 \times 10^{- 10}

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39 \times 10^{- 9}

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Solution

The correct option is D $1.5 \times 10^{- 9}$
$K s p (B a {S O}_{4}) = S^{2} {B a S O}_{4} ⇌ {B a}^{2 +} + {S o}_{4}^{2 -}$
$= {(3.9 \times 10^{- 5})}^{2}$ $S$ $S$
$= 1.52 \times 10^{- 9}$

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Similar questions

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After doing experiment, it is found that a saturated solution of BaSO4 at 25oC contains 3.9×10−5 mole/liter of Ba2+ ion. What is the value of Ksp of the BaSO4?

The correct option is D 1.5×10−9Ksp(BaSO4)=S2BaSO4⇌Ba2++So2−4 =(3.9×10−5)2 S S =1.52×10−9

After doing experiment, it is found that a saturated solution of $B a S O_{4}$ at $25^{o}$ C contains $3.9 \times 10^{- 5}$ mole $/$ liter of $B a^{2 +}$ ion. What is the value of $K_{s p}$ of the $B a S O_{4}$ ?

The correct option is D $1.5 \times 10^{- 9}$
$K s p (B a {S O}_{4}) = S^{2} {B a S O}_{4} ⇌ {B a}^{2 +} + {S o}_{4}^{2 -}$
$= {(3.9 \times 10^{- 5})}^{2}$ $S$ $S$
$= 1.52 \times 10^{- 9}$