After electrolysis of a sodium chloride solution with inner electrodes for a certain period of time, 600 mL of the 1 N solution was left which was found to be NaOH. During the same time 31.80 g of Cu was deposited in copper voltameter in series with the electrolytic cell. The % yield of NaOH obtained will be: (Atomic mass of Cu = 63.6. )
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Solution
Eq. of Cu deposited =31.8(63.6/2)=1 ∴ Eq. of NaOH formed =1 or Meq. of NaOH formed =1000 However given that 600mL of 1 NNaOH is formed, i.e., experimental yield or Meq. of NaOH=600 × 1=600 ∴ %yield 6001000×100=60%