Question

After electrolysis of a sodium chloride solution with inner electrodes for a certain period of time, 600 mL of the 1 N solution was left which was found to be NaOH. During the same time 31.80 g of Cu was deposited in copper voltameter in series with the electrolytic cell. The % yield of NaOH obtained will be: (Atomic mass of Cu = 63.6. )

Answer 1

Eq. of $Cu$ deposited $=\frac{31.8}{\left(63.6/2\right)}=1$
$\therefore$ Eq. of $NaOH$ formed $=1$
or Meq. of $NaOH$ formed $=1000$
However given that 600mL of 1 N $NaOH$ is formed, i.e., experimental yield
or Meq. of $NaOH$$=$600 $\times$ 1$=$$600$
$\therefore$ %yield $\frac{600}{1000}\times 100=60\%$