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Factors Affecting Rate Constant

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Question

After how many seconds will the concentration of the reactant in a first order reaction be halved, if the rate constant is 1.155x10 $^{- 3} s e c^{- 1}$ ?

A

600

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B

100

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C

60

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D

10

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Solution

The correct option is A 600
$t^{1} /_{2} = \frac{0.693}{k}$
$4 = \frac{0.693}{1.155 \times 10^{- 3}}$
$0.6 \times 10^{3}$
= 600

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