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Question

After inserting a dielectric inside a parallel plate capacitor, charge on the plates .

A
increases
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B
decreases
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C
remains same
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Solution

The correct option is C remains same
Because the charge is stranded in the capacitor plates, the charge cannot change. Adding the dielectric increases the capacitance by a factor of K. To see what happens to the potential difference, look at Q = C ∆V. Increasing C while keeping the charge the same means that the potential difference decreases.

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