After meeting, one ship went south and the other went west. Two hours after their meeting, they were $60$ km apart. Find the speed or each ship, if the speed of one of them is known to be $6$ km/h higher than that of the other.

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Solution

Speeds of ships be $x, x + 6$
distance covered by ships is $2 x, 2 x + 12$
since they are perpendicular $(2 x)^{2} + (2 x + 12)^{2} = 3600$
$⟹ 8 x^{2} + 48 x - 3456 = 0$
$⟹ x = 18, - 24$
Since Speeds cant be Negative speeds are $18, 24$

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After meeting, one ship went south and the other went west. Two hours after their meeting, they were 60 km apart. Find the speed or each ship, if the speed of one of them is known to be 6 km/h higher than that of the other.

Speeds of ships be x,x+6 distance covered by ships is 2x,2x+12since they are perpendicular (2x)2+(2x+12)2=3600⟹8x2+48x−3456=0⟹x=18,−24Since Speeds cant be Negative speeds are 18,24

After meeting, one ship went south and the other went west. Two hours after their meeting, they were $60$ km apart. Find the speed or each ship, if the speed of one of them is known to be $6$ km/h higher than that of the other.

Speeds of ships be $x, x + 6$
distance covered by ships is $2 x, 2 x + 12$
since they are perpendicular $(2 x)^{2} + (2 x + 12)^{2} = 3600$
$⟹ 8 x^{2} + 48 x - 3456 = 0$
$⟹ x = 18, - 24$
Since Speeds cant be Negative speeds are $18, 24$