After ozonization of a certain volume of oxygen, the volume of the oxygen was found to diminish by 500 mL. What volume of ozone was formed? What amount of heat was absorbed in its formation if $Δ H_{f}^{\circ}$ is 144.2 kJ mol $^{- 1}$ for ozone? Assume values at STP.

6.30 k J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6.35 k J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6.40 k J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6.44 k J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $6.44 k J$
$3 x O_{2} ⇌ 2 x O_{3}$
$(3 x - 2 x) = x = 500$ mL
Volume of formed $O_{3} = 1000 m L = \frac{1000}{22400}$ mol $= 0.0446$ mol
Heat absorbed $= 144.2 \times 0.0446 k J = 6.44 k J$

Suggest Corrections

Similar questions

Q. Six hundred millilitres of ozonised oxygen at

S T P

was found to weigh 1

g

. What is the volume of ozone in the ozonized oxygen?

Q. The weight of 1 litre of ozonized oxygen at STP was found to be 1.5 gm. When 100 ml of this mixture at STP was treated with turpentine oil, the volume was reduced to 90 ml. The molecular weight of ozone is:

Q. The weight of

1

L of ozonised oxygen at STP was found to be

1.5

g. When

100

mL of this mixture at STP was treated with turpentine oil, the volume reduced to

90

mL. The molecular weight of ozone is :

600

mL of ozonised oxygen at STP were found to weigh one gram. What is the volume of ozone in the ozonised oxygen?

When 20 mL of a sample of ozonised oxygen is passed through silent electric discharge, 15 mL of pure ozone gas is obtained. What was the volume of ozone in the original sample?

Join BYJU'S Learning Program

After ozonization of a certain volume of oxygen, the volume of the oxygen was found to diminish by 500 mL. What volume of ozone was formed? What amount of heat was absorbed in its formation if ΔH∘f is 144.2 kJ mol−1 for ozone? Assume values at STP.

The correct option is D 6.44 kJ3xO2⇌2xO3(3x−2x)=x=500 mLVolume of formed O3=1000 mL=100022400 mol =0.0446 molHeat absorbed =144.2×0.0446 kJ=6.44 kJ

After ozonization of a certain volume of oxygen, the volume of the oxygen was found to diminish by 500 mL. What volume of ozone was formed? What amount of heat was absorbed in its formation if $Δ H_{f}^{\circ}$ is 144.2 kJ mol $^{- 1}$ for ozone? Assume values at STP.

The correct option is D $6.44 k J$
$3 x O_{2} ⇌ 2 x O_{3}$
$(3 x - 2 x) = x = 500$ mL
Volume of formed $O_{3} = 1000 m L = \frac{1000}{22400}$ mol $= 0.0446$ mol
Heat absorbed $= 144.2 \times 0.0446 k J = 6.44 k J$