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Nomenclature of Alcohols

After reactin...

Question

After reacting with $K I$ , which of the following do not remove iodine?

C u S O_{4}

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K_{2} C r_{2} O_{7}

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H N O_{3}

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H C l

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Solution

The correct option is D $H C l$
$H C l (a q) + K I (a q) ⟶ H I (a q) + K C l (a q)$
So when $H C l$ reacts with $K I$ it forms hydrogen iodide and potassium chloride. It means the above reaction do not release Iodine.
Hence option D is correct.

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