Question

After subtracting ${\frac{1}{5}}^{th}$ portion of $a$ number from its double, we get $32$ more than the original number, find the number

• A. $40$
• B. $80$
• C. $32$
• D. $64$

Answer 1

Answer: (A)

$40$

Let numbers be x

$2x-\frac{1}{5}x=32+x$

$=\frac{10x-x}{5}=32+x$

$=9x=5\times 32+5x$

$=(9-5)x=5\times 32$

$=4x=5\times 32$

$x=5\times 8=40$

$\therefore x=40$