After the switch in the circuit below has been closed for a long time, what will be charge be on the capacitor plates?

30.0 m i c r o c o u l o m b s

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0.300 m i c r o c o u l o m b s

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150 m i c r o c o u l o m b s

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6.00 m i c r o c o u l o m b s

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1.50 m i c r o c o u l o m b s

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Solution

The correct option is A $30.0 m i c r o c o u l o m b s$
When the switch is closed for a long time, the capacitor is fully charged and no current will flow through the circuit. Thus, no voltage drop across the resistor. Therefore, the potential across the capacitor will be $10 V$ .
Thus, charge on the capacitor plates is $Q = C V = 3 (10) = 30 μ C$

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