After ……………….. years an interest of $R s 480$ would be earned for $R s 4800$ at $5 %$ $p . a$ .

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Solution

Given,
Principal, $P$ $=$ $R s 4800$
Rate of interest, $R %$ $=$ $5 %$
Interest, $I$ $=$ $R s 480$
Time, $T$ $=$ …………………..
Apply the formula, here
$T$ $=$ $\frac{100 \times I}{P \times R}$
$T$ $=$ $\frac{100 \times 480}{4800 \times 5}$
$T$ $=$ $\frac{48000}{24000}$
$T$ $=$ $2$ .
Hence the time is $2$ years.

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After ……………….. years an interest of Rs480 would be earned for Rs4800 at 5%p.a.

Given, Principal,P =Rs4800Rate of interest, R%=5%Interest,I =Rs480Time, T =…………………..Apply the formula, hereT =100×IP×RT =100×4804800×5T=4800024000 T=2.Hence the time is 2 years.

After ……………….. years an interest of $R s 480$ would be earned for $R s 4800$ at $5 %$ $p . a$ .