${A g}_{2} O + H_{2} O_{2} ⟶ 2 A g + H_{2} O + O_{2}$
In the given reaction, $H_{2} O_{2}$ acts as:

a reducing agent

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oxidising agent

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bleaching agent

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none of these

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Solution

The correct option is A a reducing agent
Hence, option $A$ is correct.

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Similar questions

H_{2} O_{2}

H_{2} O_{2} ⟶ H_{2} O + O

In reaction

$S O_{2}$ + $H_{2} S$ $\to$ $2 H_{2} O$ + $3 S$

the reducing agent is –

(i) Mn O_{2} + 4HCl \to MnC l_{2} + 2 H_{2} O + C l_{2}

(i i) CuO + H_{2} \to Cu + H_{2} O

In the reaction $A g_{2} O + H_{2} O_{2} \to 2 A g + H_{2} O + O_{2} . H_{2} O_{2}$ acts as :

2 A g + 2 H_{2} S O_{4} \to {A g}_{2} S O_{4} + 2 H_{2} O + S O_{2}

H_{2} S O_{4}

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