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Question

Ag|AgBr(s),KBr(0.01M)KCl(0.002M),AgCl(s)|Ag(s). Calculate the EMF of given cell at 25oC:
[Given: Ksp(AgCl)=4.8×1010M2,Ksp(AgBr)=2.4×1014M2 and 2.303RTF=0.06

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Solution

Given, Ksp(AgCl)=4.8×1010
[Cl()]=0.002M
[Ag+]Cl()=Ksp[Cl()]=2.4×107M
Ksp[AgBr]=2.4×1014
[Br]=0.01M
[Ag+]Br=2.4×1012M
Ag+AgClAgBr+Ag
Ecell=E00.061log[(Ag+)Br(Ag+)Cl]
Ecell=0.06log[2.4×10122.4×107]
Ecell=0.06log[105]
Ecell=+0.3V

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