Ag|Ag⊕(1M)||Ag⊕||Ag 0.5 F electricity is first passed in this LHS (anode) and 1 F of electricity is passed in the RHS (cathode) making them independent electrolytic cells at 298 K. EMF of the cell after electrolysis will:
A
increase
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B
decrease
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C
not change
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D
none of the above
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Solution
The correct option is A not change E=E⊖+0.05911log[Ag⊕]R[Ag⊕]L =0+0.0591log2=0.0591×0.301V After current is passed [Ag⊕]r=1M [Ag⊕]L=0.5M Hence, no change in EMF.