Question

$AgCl$ and $NaCl$ are colorless. $NaBr$ and $NaI$ are also colorless but $AgBr$ and $AgI$ are colored.

This is due to:

• A. ${Ag}^{+}$ polarizes ${Br}^{-}$ and $I^{-}$.
• B. ${Ag}^{+}$ has unpaired $d-$ orbital.
• C. ${Ag}^{+}$ depolarizes ${Br}^{-}$ and $I^{-}$.
• D. None of these.

Answer 1

Answer: (A)

${Ag}^{+}$ polarizes ${Br}^{-}$ and $I^{-}$.

This is because of the polarization effect.

As the size of anion increases the Ag+ polarization increases .

Thus, the colour intensity of the compound increases.

Hence,option A is correct.