Question

$AgCl$ and $NaCl$ are colourless. $NaBr$ and $NaI$ are also colourless but $AgBr$ and $AgI$ are coloured. This is because:

• A. $A{g}^{+}$ polarises $B{r}^{-}$ and $I^{-}$
• B. $A{g}^{+}$ has unpaired d-orbital
• C. $A{g}^{+}$ depolarises $B{r}^{-}$ and $I^{-}$
• D. None of above is correct

Answer 1

Answer: (A)

$A{g}^{+}$ polarises $B{r}^{-}$ and $I^{-}$

Due to smaller size and high effective nuclear charge silver ion polarises Br and I easily as they have higher size, because of this polarization they form colour charge complex.