Question

AgCl dissolved in excess of $N{H}_3,KCN$ and $N{a}_2{S}_2{O}_3$ solutions the complex produces ions:

• A. $\left[Ag\right(N{H}_3{)}_2{]}^{+},\left[Ag\right(CN{)}_2{]}^{-}$ & $\left[Ag\right(S_2{O}_3{)}_2{]}^{3-}$
• B. $\left[Ag\right(N{H}_2{)}_2{]}^{2+},\left[Ag\right(CN{)}_2{]}^{3-}$ & $\left[A{g}_4\right(S_2{O}_3{)}_5{]}^{2+}$
• C. $\left[Ag\right(N{H}_3{)}_2{]}^{2+},\left[Ag\right(CN{)}_2{]}^{+}$ & $\left[A{g}_2\right(S_2{O}_3{)}_2{]}^{2-}$
• D. $\left[Ag\right(N{H}_3{)}_4{]}^{+},\left[Ag\right(CN{)}_4{]}^{3-}$ & $\left[A{g}_2\right(S_2{O}_3{)}_2{]}^{2-}$

Answer 1

The correct option is A $\left[Ag\right(N{H}_3{)}_2{]}^{+},\left[Ag\right(CN{)}_2{]}^{-}$ & $\left[Ag\right(S_2{O}_3{)}_2{]}^{3-}$

Reactions of complex formation-

$A{g}^{+}\stackrel{N{H}_3}{\to }\left[Ag\right(N{H}_3{)}_2{]}^{+}$

AgCl dissolves in dilute ammonia solution to give the dimmine silver (l) ion:

All silver halide dissolve in thiosulphate and cyanide solutions giving thiosulphato and dicyano complexes of silver (l).

$A{g}^{+}\stackrel{C{N}^{-}}{\to }\left[Ag\right(CN{)}_2{]}^{-}$ and

$A{g}^{+}\stackrel{(S_2{O}_3{)}^{-2}}{\to }\left[Ag\right(S_2{O}_3{)}_2{]}^{-3}$

Hence,option A is correct.