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Le Chatelier's Principle for Del N Equals to 0

AgCl is solub...

Question

AgCl is soluble in $N H_{4} O H$ solution. The solubility is due to the formation of :

A g O H

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A g_{2} O

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[A g (N H_{3})_{2}]^{+}

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N H_{4} C l

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Solution

The correct option is C $[A g (N H_{3})_{2}]^{+}$
The solubility of AgCl in $N H_{4} O H$ is due to the formation of $[A g (N H_{3})_{2}]^{+}$ .

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